3.92 \(\int (d+e x^n)^2 (a+b x^n+c x^{2 n})^p \, dx\)

Optimal. Leaf size=447 \[ d^2 x \left (\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}+1\right )^{-p} \left (\frac {2 c x^n}{\sqrt {b^2-4 a c}+b}+1\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (\frac {1}{n};-p,-p;1+\frac {1}{n};-\frac {2 c x^n}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )+\frac {2 d e x^{n+1} \left (\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}+1\right )^{-p} \left (\frac {2 c x^n}{\sqrt {b^2-4 a c}+b}+1\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (1+\frac {1}{n};-p,-p;2+\frac {1}{n};-\frac {2 c x^n}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )}{n+1}+\frac {e^2 x^{2 n+1} \left (\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}+1\right )^{-p} \left (\frac {2 c x^n}{\sqrt {b^2-4 a c}+b}+1\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (2+\frac {1}{n};-p,-p;3+\frac {1}{n};-\frac {2 c x^n}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )}{2 n+1} \]

[Out]

2*d*e*x^(1+n)*(a+b*x^n+c*x^(2*n))^p*AppellF1(1+1/n,-p,-p,2+1/n,-2*c*x^n/(b-(-4*a*c+b^2)^(1/2)),-2*c*x^n/(b+(-4
*a*c+b^2)^(1/2)))/(1+n)/((1+2*c*x^n/(b-(-4*a*c+b^2)^(1/2)))^p)/((1+2*c*x^n/(b+(-4*a*c+b^2)^(1/2)))^p)+e^2*x^(1
+2*n)*(a+b*x^n+c*x^(2*n))^p*AppellF1(2+1/n,-p,-p,3+1/n,-2*c*x^n/(b-(-4*a*c+b^2)^(1/2)),-2*c*x^n/(b+(-4*a*c+b^2
)^(1/2)))/(1+2*n)/((1+2*c*x^n/(b-(-4*a*c+b^2)^(1/2)))^p)/((1+2*c*x^n/(b+(-4*a*c+b^2)^(1/2)))^p)+d^2*x*(a+b*x^n
+c*x^(2*n))^p*AppellF1(1/n,-p,-p,1+1/n,-2*c*x^n/(b-(-4*a*c+b^2)^(1/2)),-2*c*x^n/(b+(-4*a*c+b^2)^(1/2)))/((1+2*
c*x^n/(b-(-4*a*c+b^2)^(1/2)))^p)/((1+2*c*x^n/(b+(-4*a*c+b^2)^(1/2)))^p)

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Rubi [A]  time = 0.46, antiderivative size = 447, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 5, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.192, Rules used = {1436, 1348, 429, 1385, 510} \[ d^2 x \left (\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}+1\right )^{-p} \left (\frac {2 c x^n}{\sqrt {b^2-4 a c}+b}+1\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (\frac {1}{n};-p,-p;1+\frac {1}{n};-\frac {2 c x^n}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )+\frac {2 d e x^{n+1} \left (\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}+1\right )^{-p} \left (\frac {2 c x^n}{\sqrt {b^2-4 a c}+b}+1\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (1+\frac {1}{n};-p,-p;2+\frac {1}{n};-\frac {2 c x^n}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )}{n+1}+\frac {e^2 x^{2 n+1} \left (\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}+1\right )^{-p} \left (\frac {2 c x^n}{\sqrt {b^2-4 a c}+b}+1\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (2+\frac {1}{n};-p,-p;3+\frac {1}{n};-\frac {2 c x^n}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )}{2 n+1} \]

Antiderivative was successfully verified.

[In]

Int[(d + e*x^n)^2*(a + b*x^n + c*x^(2*n))^p,x]

[Out]

(2*d*e*x^(1 + n)*(a + b*x^n + c*x^(2*n))^p*AppellF1[1 + n^(-1), -p, -p, 2 + n^(-1), (-2*c*x^n)/(b - Sqrt[b^2 -
4*a*c]), (-2*c*x^n)/(b + Sqrt[b^2 - 4*a*c])])/((1 + n)*(1 + (2*c*x^n)/(b - Sqrt[b^2 - 4*a*c]))^p*(1 + (2*c*x^
n)/(b + Sqrt[b^2 - 4*a*c]))^p) + (e^2*x^(1 + 2*n)*(a + b*x^n + c*x^(2*n))^p*AppellF1[2 + n^(-1), -p, -p, 3 + n
^(-1), (-2*c*x^n)/(b - Sqrt[b^2 - 4*a*c]), (-2*c*x^n)/(b + Sqrt[b^2 - 4*a*c])])/((1 + 2*n)*(1 + (2*c*x^n)/(b -
Sqrt[b^2 - 4*a*c]))^p*(1 + (2*c*x^n)/(b + Sqrt[b^2 - 4*a*c]))^p) + (d^2*x*(a + b*x^n + c*x^(2*n))^p*AppellF1[
n^(-1), -p, -p, 1 + n^(-1), (-2*c*x^n)/(b - Sqrt[b^2 - 4*a*c]), (-2*c*x^n)/(b + Sqrt[b^2 - 4*a*c])])/((1 + (2*
c*x^n)/(b - Sqrt[b^2 - 4*a*c]))^p*(1 + (2*c*x^n)/(b + Sqrt[b^2 - 4*a*c]))^p)

Rule 429

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[a^p*c^q*x*AppellF1[1/n, -p,
-q, 1 + 1/n, -((b*x^n)/a), -((d*x^n)/c)], x] /; FreeQ[{a, b, c, d, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[n
, -1] && (IntegerQ[p] || GtQ[a, 0]) && (IntegerQ[q] || GtQ[c, 0])

Rule 510

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[(a^p*c^q
*(e*x)^(m + 1)*AppellF1[(m + 1)/n, -p, -q, 1 + (m + 1)/n, -((b*x^n)/a), -((d*x^n)/c)])/(e*(m + 1)), x] /; Free
Q[{a, b, c, d, e, m, n, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, n - 1] && (IntegerQ[p] || GtQ[a
, 0]) && (IntegerQ[q] || GtQ[c, 0])

Rule 1348

Int[((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[(a^IntPart[p]*(a + b*x^n + c*x^(2*n))
^FracPart[p])/((1 + (2*c*x^n)/(b + Rt[b^2 - 4*a*c, 2]))^FracPart[p]*(1 + (2*c*x^n)/(b - Rt[b^2 - 4*a*c, 2]))^F
racPart[p]), Int[(1 + (2*c*x^n)/(b + Sqrt[b^2 - 4*a*c]))^p*(1 + (2*c*x^n)/(b - Sqrt[b^2 - 4*a*c]))^p, x], x] /
; FreeQ[{a, b, c, n, p}, x] && EqQ[n2, 2*n] && NeQ[b^2 - 4*a*c, 0] &&  !IntegerQ[p]

Rule 1385

Int[((d_.)*(x_))^(m_.)*((a_) + (c_.)*(x_)^(n2_.) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[(a^IntPart[p]*(a +
b*x^n + c*x^(2*n))^FracPart[p])/((1 + (2*c*x^n)/(b + Rt[b^2 - 4*a*c, 2]))^FracPart[p]*(1 + (2*c*x^n)/(b - Rt[
b^2 - 4*a*c, 2]))^FracPart[p]), Int[(d*x)^m*(1 + (2*c*x^n)/(b + Sqrt[b^2 - 4*a*c]))^p*(1 + (2*c*x^n)/(b - Sqrt
[b^2 - 4*a*c]))^p, x], x] /; FreeQ[{a, b, c, d, m, n, p}, x] && EqQ[n2, 2*n]

Rule 1436

Int[((d_) + (e_.)*(x_)^(n_))^(q_)*((a_) + (b_.)*(x_)^(n_) + (c_.)*(x_)^(n2_))^(p_), x_Symbol] :> Int[ExpandInt
egrand[(d + e*x^n)^q*(a + b*x^n + c*x^(2*n))^p, x], x] /; FreeQ[{a, b, c, d, e, n, p, q}, x] && EqQ[n2, 2*n] &
& NeQ[b^2 - 4*a*c, 0] && NeQ[c*d^2 - b*d*e + a*e^2, 0] && ((IntegersQ[p, q] &&  !IntegerQ[n]) || IGtQ[p, 0] ||
(IGtQ[q, 0] &&  !IntegerQ[n]))

Rubi steps

\begin {align*} \int \left (d+e x^n\right )^2 \left (a+b x^n+c x^{2 n}\right )^p \, dx &=\int \left (d^2 \left (a+b x^n+c x^{2 n}\right )^p+2 d e x^n \left (a+b x^n+c x^{2 n}\right )^p+e^2 x^{2 n} \left (a+b x^n+c x^{2 n}\right )^p\right ) \, dx\\ &=d^2 \int \left (a+b x^n+c x^{2 n}\right )^p \, dx+(2 d e) \int x^n \left (a+b x^n+c x^{2 n}\right )^p \, dx+e^2 \int x^{2 n} \left (a+b x^n+c x^{2 n}\right )^p \, dx\\ &=\left (d^2 \left (1+\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}\right )^{-p} \left (1+\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p\right ) \int \left (1+\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}\right )^p \left (1+\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )^p \, dx+\left (2 d e \left (1+\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}\right )^{-p} \left (1+\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p\right ) \int x^n \left (1+\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}\right )^p \left (1+\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )^p \, dx+\left (e^2 \left (1+\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}\right )^{-p} \left (1+\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p\right ) \int x^{2 n} \left (1+\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}\right )^p \left (1+\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )^p \, dx\\ &=\frac {2 d e x^{1+n} \left (1+\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}\right )^{-p} \left (1+\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (1+\frac {1}{n};-p,-p;2+\frac {1}{n};-\frac {2 c x^n}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )}{1+n}+\frac {e^2 x^{1+2 n} \left (1+\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}\right )^{-p} \left (1+\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (2+\frac {1}{n};-p,-p;3+\frac {1}{n};-\frac {2 c x^n}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )}{1+2 n}+d^2 x \left (1+\frac {2 c x^n}{b-\sqrt {b^2-4 a c}}\right )^{-p} \left (1+\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )^{-p} \left (a+b x^n+c x^{2 n}\right )^p F_1\left (\frac {1}{n};-p,-p;1+\frac {1}{n};-\frac {2 c x^n}{b-\sqrt {b^2-4 a c}},-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}}\right )\\ \end {align*}

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Mathematica [A]  time = 0.75, size = 338, normalized size = 0.76 \[ \frac {x \left (\frac {-\sqrt {b^2-4 a c}+b+2 c x^n}{b-\sqrt {b^2-4 a c}}\right )^{-p} \left (\frac {\sqrt {b^2-4 a c}+b+2 c x^n}{\sqrt {b^2-4 a c}+b}\right )^{-p} \left (a+x^n \left (b+c x^n\right )\right )^p \left ((n+1) \left (d^2 (2 n+1) F_1\left (\frac {1}{n};-p,-p;1+\frac {1}{n};-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}},\frac {2 c x^n}{\sqrt {b^2-4 a c}-b}\right )+e^2 x^{2 n} F_1\left (2+\frac {1}{n};-p,-p;3+\frac {1}{n};-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}},\frac {2 c x^n}{\sqrt {b^2-4 a c}-b}\right )\right )+2 d e (2 n+1) x^n F_1\left (1+\frac {1}{n};-p,-p;2+\frac {1}{n};-\frac {2 c x^n}{b+\sqrt {b^2-4 a c}},\frac {2 c x^n}{\sqrt {b^2-4 a c}-b}\right )\right )}{(n+1) (2 n+1)} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[(d + e*x^n)^2*(a + b*x^n + c*x^(2*n))^p,x]

[Out]

(x*(a + x^n*(b + c*x^n))^p*(2*d*e*(1 + 2*n)*x^n*AppellF1[1 + n^(-1), -p, -p, 2 + n^(-1), (-2*c*x^n)/(b + Sqrt[
b^2 - 4*a*c]), (2*c*x^n)/(-b + Sqrt[b^2 - 4*a*c])] + (1 + n)*(e^2*x^(2*n)*AppellF1[2 + n^(-1), -p, -p, 3 + n^(
-1), (-2*c*x^n)/(b + Sqrt[b^2 - 4*a*c]), (2*c*x^n)/(-b + Sqrt[b^2 - 4*a*c])] + d^2*(1 + 2*n)*AppellF1[n^(-1),
-p, -p, 1 + n^(-1), (-2*c*x^n)/(b + Sqrt[b^2 - 4*a*c]), (2*c*x^n)/(-b + Sqrt[b^2 - 4*a*c])])))/((1 + n)*(1 + 2
*n)*((b - Sqrt[b^2 - 4*a*c] + 2*c*x^n)/(b - Sqrt[b^2 - 4*a*c]))^p*((b + Sqrt[b^2 - 4*a*c] + 2*c*x^n)/(b + Sqrt
[b^2 - 4*a*c]))^p)

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fricas [F]  time = 1.04, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (e^{2} x^{2 \, n} + 2 \, d e x^{n} + d^{2}\right )} {\left (c x^{2 \, n} + b x^{n} + a\right )}^{p}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d+e*x^n)^2*(a+b*x^n+c*x^(2*n))^p,x, algorithm="fricas")

[Out]

integral((e^2*x^(2*n) + 2*d*e*x^n + d^2)*(c*x^(2*n) + b*x^n + a)^p, x)

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giac [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d+e*x^n)^2*(a+b*x^n+c*x^(2*n))^p,x, algorithm="giac")

[Out]

Exception raised: TypeError >> An error occurred running a Giac command:INPUT:sage2:=int(sage0,x):;OUTPUT:Unab
le to divide, perhaps due to rounding error%%%{128,[1,0,5,3,5,4,1,6,1]%%%}+%%%{512,[1,0,5,3,5,3,1,6,1]%%%}+%%%
{768,[1,0,5,3,5,2,1,6,1]%%%}+%%%{512,[1,0,5,3,5,1,1,6,1]%%%}+%%%{128,[1,0,5,3,5,0,1,6,1]%%%}+%%%{-96,[1,0,5,3,
4,4,3,5,1]%%%}+%%%{-384,[1,0,5,3,4,3,3,5,1]%%%}+%%%{-576,[1,0,5,3,4,2,3,5,1]%%%}+%%%{-384,[1,0,5,3,4,1,3,5,1]%
%%}+%%%{-96,[1,0,5,3,4,0,3,5,1]%%%}+%%%{24,[1,0,5,3,3,4,5,4,1]%%%}+%%%{96,[1,0,5,3,3,3,5,4,1]%%%}+%%%{144,[1,0
,5,3,3,2,5,4,1]%%%}+%%%{96,[1,0,5,3,3,1,5,4,1]%%%}+%%%{24,[1,0,5,3,3,0,5,4,1]%%%}+%%%{-2,[1,0,5,3,2,4,7,3,1]%%
%}+%%%{-8,[1,0,5,3,2,3,7,3,1]%%%}+%%%{-12,[1,0,5,3,2,2,7,3,1]%%%}+%%%{-8,[1,0,5,3,2,1,7,3,1]%%%}+%%%{-2,[1,0,5
,3,2,0,7,3,1]%%%}+%%%{64,[1,0,5,2,5,3,1,6,1]%%%}+%%%{192,[1,0,5,2,5,2,1,6,1]%%%}+%%%{192,[1,0,5,2,5,1,1,6,1]%%
%}+%%%{64,[1,0,5,2,5,0,1,6,1]%%%}+%%%{-48,[1,0,5,2,4,3,3,5,1]%%%}+%%%{-144,[1,0,5,2,4,2,3,5,1]%%%}+%%%{-144,[1
,0,5,2,4,1,3,5,1]%%%}+%%%{-48,[1,0,5,2,4,0,3,5,1]%%%}+%%%{12,[1,0,5,2,3,3,5,4,1]%%%}+%%%{36,[1,0,5,2,3,2,5,4,1
]%%%}+%%%{36,[1,0,5,2,3,1,5,4,1]%%%}+%%%{12,[1,0,5,2,3,0,5,4,1]%%%}+%%%{-1,[1,0,5,2,2,3,7,3,1]%%%}+%%%{-3,[1,0
,5,2,2,2,7,3,1]%%%}+%%%{-3,[1,0,5,2,2,1,7,3,1]%%%}+%%%{-1,[1,0,5,2,2,0,7,3,1]%%%}+%%%{128,[0,0,5,2,5,3,0,7,1]%
%%}+%%%{384,[0,0,5,2,5,2,0,7,1]%%%}+%%%{384,[0,0,5,2,5,1,0,7,1]%%%}+%%%{128,[0,0,5,2,5,0,0,7,1]%%%}+%%%{-96,[0
,0,5,2,4,3,2,6,1]%%%}+%%%{-288,[0,0,5,2,4,2,2,6,1]%%%}+%%%{-288,[0,0,5,2,4,1,2,6,1]%%%}+%%%{-96,[0,0,5,2,4,0,2
,6,1]%%%}+%%%{24,[0,0,5,2,3,3,4,5,1]%%%}+%%%{72,[0,0,5,2,3,2,4,5,1]%%%}+%%%{72,[0,0,5,2,3,1,4,5,1]%%%}+%%%{24,
[0,0,5,2,3,0,4,5,1]%%%}+%%%{-2,[0,0,5,2,2,3,6,4,1]%%%}+%%%{-6,[0,0,5,2,2,2,6,4,1]%%%}+%%%{-6,[0,0,5,2,2,1,6,4,
1]%%%}+%%%{-2,[0,0,5,2,2,0,6,4,1]%%%} / %%%{64,[0,0,5,3,5,3,0,6,0]%%%}+%%%{192,[0,0,5,3,5,2,0,6,0]%%%}+%%%{192
,[0,0,5,3,5,1,0,6,0]%%%}+%%%{64,[0,0,5,3,5,0,0,6,0]%%%}+%%%{-48,[0,0,5,3,4,3,2,5,0]%%%}+%%%{-144,[0,0,5,3,4,2,
2,5,0]%%%}+%%%{-144,[0,0,5,3,4,1,2,5,0]%%%}+%%%{-48,[0,0,5,3,4,0,2,5,0]%%%}+%%%{12,[0,0,5,3,3,3,4,4,0]%%%}+%%%
{36,[0,0,5,3,3,2,4,4,0]%%%}+%%%{36,[0,0,5,3,3,1,4,4,0]%%%}+%%%{12,[0,0,5,3,3,0,4,4,0]%%%}+%%%{-1,[0,0,5,3,2,3,
6,3,0]%%%}+%%%{-3,[0,0,5,3,2,2,6,3,0]%%%}+%%%{-3,[0,0,5,3,2,1,6,3,0]%%%}+%%%{-1,[0,0,5,3,2,0,6,3,0]%%%} Error:
Bad Argument Value

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maple [F]  time = 0.10, size = 0, normalized size = 0.00 \[ \int \left (e \,x^{n}+d \right )^{2} \left (b \,x^{n}+c \,x^{2 n}+a \right )^{p}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x^n+d)^2*(b*x^n+c*x^(2*n)+a)^p,x)

[Out]

int((e*x^n+d)^2*(b*x^n+c*x^(2*n)+a)^p,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (e x^{n} + d\right )}^{2} {\left (c x^{2 \, n} + b x^{n} + a\right )}^{p}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d+e*x^n)^2*(a+b*x^n+c*x^(2*n))^p,x, algorithm="maxima")

[Out]

integrate((e*x^n + d)^2*(c*x^(2*n) + b*x^n + a)^p, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int {\left (d+e\,x^n\right )}^2\,{\left (a+b\,x^n+c\,x^{2\,n}\right )}^p \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((d + e*x^n)^2*(a + b*x^n + c*x^(2*n))^p,x)

[Out]

int((d + e*x^n)^2*(a + b*x^n + c*x^(2*n))^p, x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((d+e*x**n)**2*(a+b*x**n+c*x**(2*n))**p,x)

[Out]

Timed out

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